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A conundrum

Name: Anonymous 2009-12-09 5:37

'soup, /sci/? I've got a problem. I'm talking to this girl, and she's apparently some kind of math nerd who likes probability. She's got three pieces of paper, and wrote her phone number down on one. She knows which has her number, and which two don't. She asked me to pick one, then got rid of one of the wrong choices. After that, she asked if I wanted to change the one I picked, or go with it. I'd either get her number--or not.
Now, I'm no genius, but I'm going a little nuts here. At first, there was a 1/3 change of getting her number, but there was a 2/3 chance of getting to know Rosey Palm better.
Is there now a 1/2 shot that the paper I picked has her number, or is it still a 1/3 based on the circumstances of my last selection?
WHAT SHOULD I DO?

Name: Anonymous 2009-12-09 6:12

If you spent as much effort solving your homework as you did disguising your questions, you would be better off

Name: Anonymous 2009-12-09 10:59

>>1
>girl
>math nerd
almost got me

Name: Anonymous 2009-12-09 12:47

old faggotry. there is no difference. You never knew which one was right to begin with so the mathematical probabilities of 2/3 and 1/2 don't mean shit.

Name: Anonymous 2009-12-09 15:15

>>4
This man is full of shit.

Name: Anonymous 2009-12-10 0:19

When you started, your first choice had a 1/3 chance of being correct. The other two had a 2/3 of being correct. When she eliminated one, the other choice still retains that 2/3 chance while the choice you picked still has the 1/3. Pick the other one.

Name: Anonymous 2009-12-15 3:47

I'm talking to this girl

That's one, fag.



who likes probability

you're shot with her is asymptotic in a not-good way



I'm no genius

Glad you have a grasp of the self evident... or do you, fag?

Don't change these.
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