Chemistry
Name:
Anonymous
2009-03-22 22:06
2KCN + MgBr2 ---> Mg(CN)2 + 2KBr
KCN = 458 mL 0.389M concentration
MgBr2 = 20 mL 0.425M concentration
0.3829g Magnesium Cyanide is formed, 59% yield.
How do I figure out the molarity of the KBr solution?
Name:
Anonymous
2009-03-22 23:10
STOICHIOMETRY
Name:
OP
2009-03-23 0:14
Thanks, I know that much :p that's how I found the % yield...
I don't know how to set up the stoichiometry to find the molarity.
In fact I run into trouble whenever I'm converting anything to liters or molarity...
Halp pls! Quiz at 11am tomorrow!
Name:
Anonymous
2009-03-23 6:14
you should be underage b&d or something.
HINT: n=m/Mr
Name:
OP
2009-03-23 7:38
>>4
Well apparently I am Underage B7 because that didn't help.
Name:
Anonymous
2009-03-23 21:54
lol convert to moles kneegrow
Name:
Anonymous
2009-03-25 21:45
find grams of kbr made and volume using stoich, convert grams to moles divide by liters of kbr. ;)