Name: Anonymous 2009-03-22 22:06
2KCN + MgBr2 ---> Mg(CN)2 + 2KBr
KCN = 458 mL 0.389M concentration
MgBr2 = 20 mL 0.425M concentration
0.3829g Magnesium Cyanide is formed, 59% yield.
How do I figure out the molarity of the KBr solution?
KCN = 458 mL 0.389M concentration
MgBr2 = 20 mL 0.425M concentration
0.3829g Magnesium Cyanide is formed, 59% yield.
How do I figure out the molarity of the KBr solution?