Beginners Calculus

lim(x)  (3x^3+x^2-4)/(x^2-1)    x    lim(x)  (x-3)/((x^2-1)^.5 -2)
x -> 1                               x -> 3

Question is: are the product of limits < 0 ?

I say no because in the second part, as x -> 3 the limit is 0
(?)0 < 0
0 < 0
No.

Or am I doing it wrong? :X

PS Teech me sum math short hands for limitz plx :(

L'Hospitals rule makes limits easy

As you've written it the problem says to first calculate the limits, then just multiply the two numbers together. No funny business there, so I'd say you're doing it exactly right.
"math short hands" wha?

Just wondering if there was an easier way to write

lim(x)
x->1

instead of guessing with spaces (as you can see my x->3 if you don't have the page font to courier new)

Or would you just say

lim(x) as x->1 (numbers)

>>6
Yeah, pretty much. You can get fancy with BBCode, and write lim_x->0 x
(lim[sub]x->0[/sub] x)

>>7
How do you get the BBCode to not evaluate without stuff breaking everywhere?

>>8
That was done with the [code] tag.
For more complicated things you can break the tags by doing something like [/code[b][/b]