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Numbers and Subfields

Name: Anonymous 2007-04-09 12:31 ID:jkUTkTMW

Bryce Bolin

 
 
7..7 (a)

 

There exist no subfield K of C with R ⊂ K ⊂ C and R =/= K =/= C.


a,b € R

a+b € R, K,C, as defined for the confines above with R,K and C being fields.

      b(i)= bi

 (a) + bi = a + bi

a + bi € C, K but not for R

So with R  ⊂ K ⊂ C, it is not possible for K to be a subfield of C.

Name: Anonymous 2007-04-09 21:02 ID:VROX3rQn

Dim[ C : R ] = 2  A proper subfield K would have to have dimension d over R with d dividing 2.  d = 1 => K = R.  d = 2 => K = C.

Suck cock and die.

Name: Anonymous 2007-04-10 6:51 ID:kN5bMQsw

C is complex. R is real.

Name: Anonymous 2007-04-10 16:03 ID:Yx9oQHTA

>>2
FRACTALS FRACTALS FRACTALS FRACTALS FRACTALS

Name: Anonymous 2007-04-10 17:32 ID:AMDXq5CT

>>4
Fractals aren't fields.

Name: Anonymous 2007-04-11 10:43 ID:ZIugtR8U

>>5
However, fields are fractals.

Name: Anonymous 2007-04-11 14:05 ID:CnfzTHr4

1+1=5

Name: Anonymous 2007-04-11 14:06 ID:CnfzTHr4

2+2=4

Name: Anonymous 2007-04-11 14:06 ID:CnfzTHr4

3+3=3

Name: Anonymous 2009-03-18 2:24

The word pirahna, is all I can think of that rhymes with marijuana

Marijuana MUST be legalized.

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