Proof of 1 Not equal 0.999...

0*infinity=(0+0+0+0...)=0 (x+0=x x=0)
1=0.999... (agreed) 1-0.999...=0
(type 1) 1-0.999...=(1/10)*(1/10)*(1/10)... (from division by 10, 1-0.9 etc)
ab=0 if a or b=0; 1/10=0 ;10*1/10=10*0 ;1=0 ;x*1=x*0 ;x=0
(type 2) (1/10)*(1/10)*(1/10) ...=(1/10)^infinity=1/infinity=0
1/infinity=0 then 0*infinity=1 bu 0*infinity=0 ;1=0 ;x*1=x*0; x=0
Every number equals zero .(by 1=0.999...)

Infinity isn't a number, you fail at life, gtfo and kill yourself.

If wikipedia uses it as number in equations then its a number.
See wikipedia article on infinity.

Wikipedia defines x/infinity=0
http://en.wikipedia.org/wiki/Infinity#Operations_involving_infinity_and_a_real_number_x
Start killing yourself,because you fail.
Take this rope.

>>4
"Infinity is not a real number"

Thanks for proving my point. Kill yourself. Now.

i Not care if its real number,wikipedia uses it as number and so do I.
When you disprove wikipedia article,you can return to this thread.

infinity is only treated as a number in the extended real number line, as wikipedia says. The example x/infinity-0 is not correct, it should be:

lim n->infinity x/n = 0

This is not in the wiki.It specificially says these are operations with infinity and Number X.

Besides if its a lim(n->infinity) x/n=0 then it must be true for infinite x.

Stop getting trolled, idiots.

You can't deny the truth.

>>1
>>3
>>4
>>6
>>8
>>9
>>11
fucking die

>>12
After you.(in unspecified time x after)

>>6
We're all talking about real numbers. If you want to take another system, be my guest. It's like arguing that 1 + 1 = 0 because it's true in the field with two elements.

>>14
Only in binary.I'm always using real number of the decimal system.
If you like you can substitute infinity by N,in any of the lines and they still
hold.

>>15
Infinity isn't a real number. If you're using the real number system you can't just go "LOL MULTIPLY BY INFINITY" because Wikipedia states some OTHER SYSTEM allows multiplication by infinity, any more than you could say "1 + 1 = 0" just because some OTHER SYSTEM allows this.

Furthermore, 1+1 = 10 in binary you uneducated inbred mouthbreather.

>Infinity isn't a real number.
If i can use it as variable,its fine.Else variable N(infinitely large)
.
If you're using the real number system you can't just go "LOL >MULTIPLY BY INFINITY" because Wikipedia states some OTHER >SYSTEM allows multiplication by infinity, any more than you could say >"1 + 1 = 0" just because some OTHER SYSTEM allows this.
Of course i can,wikipedia can.So do i.

>Furthermore, 1+1 = 10 in binary you uneducated inbred mouthbreather.
1  carries over.see the next digit.

If you read post >>4
You can clearly see the section title.here i'll help you.
http://en.wikipedia.org/wiki/Infinity#Operations_involving_infinity_and_a_real_number_x
Operations (equations)
Involving (containing numbers)
Infinity (concept of arbitraly large number)
and (also containing)
a (noun prefix)
Real (reals as in fracitonal decimal,with dot.)
Number (abstract representation of quantity)
X (a variable)

>>18
>>17
"Infinity is not a real number but the extended real number line adds two elements called infinity"

Extended real number line != real number line. GTFO Troll

Whats the matter,you can't handle infinity being in equations with real number X?
Something wrong with you?
Wikipedia uses infinity with real numbers.
I use them with real numbers.
Only sad idiots can't use it because their religion doesn't allow it.
"I can't use infinity in calculations because God forbids it"

>>20
Listen, I'm explaining this one last time: The real numbers and the extended real numbers are TWO DIFFERENT THINGS. You can't say "wow look, A is true in the extended real numbers so it must be true in the real numbers too!" which is EXACTLY WHAT YOU ARE DOING. Once again, it's like saying 1 + 1 = 0 in the real numbers because 1 + 1 = 0 in F2. Of course, you probably don't even know what a field is because you're a useless uneducated cunt. FOAD.

>>21
Read post >>6

I'm really surprised that no one has called him on being unable to argue without Wikipedia's cock in his mouth.

The problem is that mathfags assume they can forbid equations with infinity.While they are commonly used.
Its like forbidding to use powers of 2.Really stupid.

Except powers of 2 are real numbers and on the real number line. Infinity is not. You're not even reading the source you're clinging so tightly to.

Number 21 speaks total truth. Lrn2math.

Come on, this is such an obvious troll. Everybody knows that anybody who argues against .999.. = 1 on /sci is just trolling.

Come on,the earth is flat.Everybody knows that anybody who argues against that the earth is flat is just trolling.Lets burn him and his books.

>>28
Well, that was a compelling argument.

FrozenVoid lieks wikipedia's semen

Using the same logic of this thread here's the proof of 3=5

3*0=5*0 => 3=5

>>1
1/10=/0 (lim(n->infinity)1/(10^n)=0)
1=/0
let x = 1
x = x^2
x-1 = x^2-1
(x-1) = (x-1)*(x+1)
1 = x+1
0 = x = 1 But
1-1 = (1-1)*(1+1)
0 = 2+0
0/0 = (2+0)/0
1 = 2
0 = 1
you pulling the same fail math as above.

also infinity/infinity and 0*infinity are any real numbers, not just 1 or 0. They're called indeterminate forms, look them up http://en.wikipedia.org/wiki/Indeterminate_form

>>31
>>32
These examples are not disproving my argument,they are
completely absurd and only purpose is equate the argument to non-sense.
Please grow up and drop your stupid analogies that make no sense whatsoever.There is no single line of my argument so far,you didn't
disprove.Let me refresh the course.

0*infinity=(0+0+0+0...)=0 (x+0=x x=0)
Adding infinite zeros is equivalent to adding zero.Case closed.

1=0.999... (agreed) 1-0.999...=0
Equation Assumed to be true,be we show the absurdity of it in the following transformation. Difference between equals is zero

(type 1) 1-0.999...=(1/10)*(1/10)*(1/10)... (from division by 10, 1-0.9 etc)
The difference between "equals" is also a infinite series

ab=0 if a or b=0; 1/10=0 ;10*1/10=10*0 ;1=0 ;x*1=x*0 ;x=0
The multiplication results is zero,only is of one of the members is zero.
The only member is 1/10 so it equates zero.Following shows we proof now every number equals zero. Absurd? As 0.999...=1

(type 2) (1/10)*(1/10)*(1/10) ...=(1/10)^infinity=1/infinity=0
The series can be represented by (1/10)^n (n which grows to infinity)
 converted to 1/infinity And assumed to be equal to zero)by 1-0.999...).

1/infinity=0 then 0*infinity=1 bu 0*infinity=0 ;1=0 ;x*1=x*0; x=0
This result is in contradiction with first (see line with 0*infinity=0) bringing
1 in euality with 0,proving that:

Every number equals zero .(by 1=0.999...)

For your type one argument:
Correct:
1-.099999... = 0
Incorrect:
lim(x->infinity)(1/(10^x))=something not 0
Correct:
lim(x->infinity)(1/(10^x))= 0
Informal proof:
plug in numbers for f(x)=1/(10^x)
x          f(x)
1          .1
2          .01
3          .001
4          .0001
5          .00001
...        ...
"infinity" 0
As x approaches infinity, f(x) approaches the x-axis and when x "meets" infinity, f(x) "meets" the x-axis and because the x axis is the line y = 0 and f(x) = y then f(x) = y = 0 = x axis and therefore f(x) = 0. Keep in mind that no organism (even if they had billions of years or more to do it) can count to infinity by integral values; it's that far away. Yet, by 5, f(x) is already one hundred thousandth and by 100, f(x) is one googleth. By the time one would "reach" infinity, f(x) ceases to exist and is zero.

As for second type:
Incorrect: infinity/infinity must equal 1.
Correct: infinity/infinity can equal any real number.
proof:
lim(x->infinity)(3*x/x)
direct substitution yields: infinity/infinity (n multiplied by infinity is infinity) which if x/x = 1, then lim(x-infinity)(3*x/x) should equal one.
reduce: lim(x->infinity)(3)(allowable since 3x/x = 3 except for x = 0, but we're heading away from zero, not towards it).
take limit:lim(x->infinity)(3)= 3
3 =/ 1, the limit of the function 3x/x appears to have two answers yet f(x) is a function and cannot have two y-values defined for any x-value ("infinity" in this case). Which limit is it? Well f(x)=3x/x equals f(x)=3 for all numbers except x=0 and plugging x's into 3x/x yields
x    f(x)
1    3
2    3
3    3
4    3
5    3
6    3
...  ...

I wonder if it'll be 3 at infinity or 1?
infinity/infinity = 3 in this case.

lim(x->infinity)(1/(10^x))=something not 0
Where did you find those limits? I didn't mention them.
Where do you reach zero?its infinitely away."As x approaches infinity"
DId you just say limit=result?

Incorrect: infinity/infinity must equal 1.
Where did you find this? I only mention 1/infinity=0 (becuase of 1-0.999..=0) and 0*infinity=0  which both prove (by a/b=c then cb=a)
that 1=0.

>>35
when you said:
>>1
1-0.999...=(1/10)*(1/10)*(1/10)... (from division by 10, 1-0.9 etc)
I intepreted this to mean that:
1-.9 = .1
1-.99 = .01
1-.999 = .001
1-.9999 = .0001
1-99999... = .0000...
such that the pattern is 1-.9999... = lim(x->infinity)(1/(10^x))
Becuase if you meant that:
1-.9 = 1/10
1-.99 = 1/10
1-.999 = 1/10
1-.9999 = 1/10
etc.
Then you need to use a calculator or something because 1-.99 =1/100.
Also, you "reach" zero at the same point at which you "reach" infinity: the infinitly far away. Any positive real number put into 1/(10^x) will return a real number (albiet one very small real number) but when infinity goes into 1/(10^x), you get 0 because the infinitly small is considered to be nonexistant (take the smallest thing possible, cut it in two, what's left? another "smallest thing possible" or nothing? if the former, then you didn't start with the "smallest thing possible").

>>35
"Incorrect: infinity/infinity must equal 1.
Where did you find this?"
right here:
"1/infinity=0 then 0*infinity=1"
because these are the steps you have to take:
1/infinity = 0
(1/infinity)*infinity = 0*infinity
1*(infinity/infinity) = 0*infinity
(next step is not always true)
1*(1)=0*infinity
1=0*infinity

What number exists between 0.999... and 1 on the real number line?

>>37
0.999...0,obviously.

>>38
If you're going to troll, try harder.

>>33
Stop being fucking absurd
"0*infinity=(0+0+0+0...)=0 "
Again, INFINITY IS NOT A FUCKING NUMBER, even if we consider the extension of reals, 0*infinity is indetermined. Your loved wikipedia will show it to you http://en.wikipedia.org/wiki/Infinity

1=0.999... (agreed) 1-0.999...=0
Equation Assumed to be true,be we show the absurdity of it in the following transformation. Difference between equals is zero

"ab=0 if a or b=0; 1/10=0 ;10*1/10=10*0 ;1=0 ;x*1=x*0 ;x=0
The multiplication results is zero,only is of one of the members is zero."
Total failure, ab are just 2 elements, and you have infinite of them, and no, you cant group infinite elements..."

"1/infinity=0 then 0*infinity=1 bu 0*infinity=0 ;1=0 ;x*1=x*0; x=0"
RIIIIIIIIIGHT, again, infinity is not a number, and, even if we consider a extension of reals, infinity/infinity is indetermined.

Now, quit math and go kill yourself