Proof of 1 Not equal 0.999...

0*infinity=(0+0+0+0...)=0 (x+0=x x=0)
1=0.999... (agreed) 1-0.999...=0
(type 1) 1-0.999...=(1/10)*(1/10)*(1/10)... (from division by 10, 1-0.9 etc)
ab=0 if a or b=0; 1/10=0 ;10*1/10=10*0 ;1=0 ;x*1=x*0 ;x=0
(type 2) (1/10)*(1/10)*(1/10) ...=(1/10)^infinity=1/infinity=0
1/infinity=0 then 0*infinity=1 bu 0*infinity=0 ;1=0 ;x*1=x*0; x=0
Every number equals zero .(by 1=0.999...)

>>31
>>32
These examples are not disproving my argument,they are
completely absurd and only purpose is equate the argument to non-sense.
Please grow up and drop your stupid analogies that make no sense whatsoever.There is no single line of my argument so far,you didn't
disprove.Let me refresh the course.

0*infinity=(0+0+0+0...)=0 (x+0=x x=0)
Adding infinite zeros is equivalent to adding zero.Case closed.

1=0.999... (agreed) 1-0.999...=0
Equation Assumed to be true,be we show the absurdity of it in the following transformation. Difference between equals is zero

(type 1) 1-0.999...=(1/10)*(1/10)*(1/10)... (from division by 10, 1-0.9 etc)
The difference between "equals" is also a infinite series

ab=0 if a or b=0; 1/10=0 ;10*1/10=10*0 ;1=0 ;x*1=x*0 ;x=0
The multiplication results is zero,only is of one of the members is zero.
The only member is 1/10 so it equates zero.Following shows we proof now every number equals zero. Absurd? As 0.999...=1

(type 2) (1/10)*(1/10)*(1/10) ...=(1/10)^infinity=1/infinity=0
The series can be represented by (1/10)^n (n which grows to infinity)
 converted to 1/infinity And assumed to be equal to zero)by 1-0.999...).

1/infinity=0 then 0*infinity=1 bu 0*infinity=0 ;1=0 ;x*1=x*0; x=0
This result is in contradiction with first (see line with 0*infinity=0) bringing
1 in euality with 0,proving that:

Every number equals zero .(by 1=0.999...)