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Proof of 1 Not equal 0.999...

Name: FrozenVoid 2007-03-01 8:54 ID:fPuNCwa3

0*infinity=(0+0+0+0...)=0 (x+0=x x=0)
1=0.999... (agreed) 1-0.999...=0
(type 1) 1-0.999...=(1/10)*(1/10)*(1/10)... (from division by 10, 1-0.9 etc)
ab=0 if a or b=0; 1/10=0 ;10*1/10=10*0 ;1=0 ;x*1=x*0 ;x=0
(type 2) (1/10)*(1/10)*(1/10) ...=(1/10)^infinity=1/infinity=0
1/infinity=0 then 0*infinity=1 bu 0*infinity=0 ;1=0 ;x*1=x*0; x=0
Every number equals zero .(by 1=0.999...)

Name: Anonymous 2007-03-03 13:47 ID:EPaNpJoA

>>1
1/10=/0 (lim(n->infinity)1/(10^n)=0)
1=/0
let x = 1
x = x^2
x-1 = x^2-1
(x-1) = (x-1)*(x+1)
1 = x+1
0 = x = 1 But
1-1 = (1-1)*(1+1)
0 = 2+0
0/0 = (2+0)/0
1 = 2
0 = 1
you pulling the same fail math as above.

also infinity/infinity and 0*infinity are any real numbers, not just 1 or 0. They're called indeterminate forms, look them up http://en.wikipedia.org/wiki/Indeterminate_form

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