How many solutions are there to the equation e^x+1=x^e+1(x being the unknown and e being the base of the natural logarithm, a constant)? If you answer this question within 5 seconds, you're good.
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Anonymous2007-02-28 4:52 ID:bAf9dbfl
None. That was easy.
PROTIP: If you think it's necessary to explain what e and x are, you're not qualified to either ask these questions or decide who is and isn't 'good'.
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Anonymous2007-02-28 6:23 ID:kK1vOj1B
Sorry, I got my question wrong. The question should be "How many solutions are there to the equation e^(x+1)=x^(e+1)?"
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Anonymous2007-02-28 6:24 ID:kK1vOj1B
People may think that e stands for an unknown,not the natural constant.
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Anonymous2007-02-28 6:25 ID:smVff99U
e^x+1=x^e+1
e^x=x^e
x=e
Name:
Anonymous2007-02-28 6:27 ID:kK1vOj1B
Correct! You're good.
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Anonymous2007-03-01 2:56 ID:Uz1BNYq+
>>4
Then those people shouldn't be answering these questions. e isn't used as a variable because it is an important constant.
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Anonymous2007-03-01 13:38 ID:U+QAPCdU
>>7
Actually >>1 shouldn't be asking the questions without beforehand stating that e is the natural constant.