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e^x+1=x^e+1

Name: Anonymous 2007-02-28 4:40 ID:kK1vOj1B

How many solutions are there to the equation e^x+1=x^e+1(x being the unknown and e being the base of the natural logarithm, a constant)? If you answer this question within 5 seconds, you're good.

Name: Anonymous 2007-02-28 6:24 ID:kK1vOj1B

People may think that e stands for an unknown,not the natural constant.
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