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Ack, stupid question

Name: JasonO 2007-02-03 21:06

Ive been working on this and i cant quite figure it out, and it doesnt explain it inside the unit.

"Square JKLM is inscribed in P. If JL = 30, calculate the area outside the square but inside the circle."

the line JL goes right through the corners of the insribed square.

I may have started completely wrong but heres how i started. i first saw that the JL is also the diameter of the circle, radius is 15, area of the circle is easy, but now i gotta deal with the square, split the square into 4 triangles, all 90-45-45 triangls, with 2 sides 15 units long. 15^2+15^2=c^2, i got 450^2= 21.2132034(i do something wrong?) then get the area of the circle, 42.4264068, now the circles area minus the 42...where did i go wrong?

Name: Anonymous 2007-02-03 22:36

er

the diameter would be 42, so radius 21

21^2 * pi - 30^2=484.74

Name: Anonymous 2007-02-03 22:41

>>2

..no

Name: Anonymous 2007-02-03 23:16

square's diagonal = 30
area of circle = 15^2 * pi = 706.86
area of square = sqrt(30^2 /2)^2 = 450
area outside of square, inside circle = 706.86 - 450 ~= 257

Name: OP 2007-02-03 23:44

Thats it, 4s right, thank you very much

Name: Anonymous 2007-02-04 0:44 (sage)

>>1,2
THIS SITE IS FOR ADULTS

Name: 4tran 2007-02-04 0:56

>>6
WE KNOW THAT; MAYBE YOU SHOULD BE LEAVING SOON

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