The x is squared to convert any negative x to a positive value.
The negative is applied so that the power will be smaller for increasing x.
The exponent has *x so that if x is zero, the exponent is zero, and the power works out to one.
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Anonymous2006-11-11 15:44
er, I just figured out that my last comment above about *x shouldn't be that *x makes the exponent zero when x is zero, because it would be zero anyway. What it does do is ensure the value of the function decreases for increasing x, regardless if x is negative or not.
>>4,5 not linear and totally wrong, dumbshit >>3 ...what the fuck are you talking about?
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Anonymous2006-11-11 16:28
>>6
Oh, linear. I neglected that part. Oh, and fuck you asshole
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Anonymous2006-11-11 16:36
>>6
And another thing, go fuck yourself. The OP didn't mention linear in his sentence so I neglected that requirement, not recalling the subject title as I was thinking. My function works according to the restrictions fine. It's just not linear.
Oh, and fuck you
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Anonymous2006-11-11 16:41
Anyway, I found a simpler function, which also isn't linear (eat it >>6):
f(x) = -(x^3) + 1
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Anonymous2006-11-11 18:43
>>1
If it's linear, than f(x+y) = f(x)+f(y). So 1 = f(0) = f(0+0) = f(0) + f(0) = 1+1 = 2.
If linearity isn't actually required, refer to >>9.
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Anonymous2006-11-13 0:44
>>10
I think by "linear," the OP meant "first order polynomial" rather than "linear map."