I hope this is allowed
Name:
Anonymous
2011-10-11 22:04
I tried to find the rules for this board, but couldn't find them.
I hope I'm not breaking any. I also hope someone can help me (/sci/ doesn't allow these threads).
Can you help me with a tiny math problem?
log((x+y)/3)=(1/2)(log(x)+log(y)), determine the value of x/y
I keep ending up with (x^2)+(y^2)-(7xy)=0
any suggestions? It's driving me nuts...
Name:
Anonymous
2011-10-11 22:13
wolframalpha.com?
Name:
Anonymous
2011-10-11 22:17
Why didn't you visit the textboard /sci/ instead of the programming board?
Name:
Anonymous
2011-10-11 22:20
because it's against /sci/ rules
I'm just trying not to break any rules
Name:
Anonymous
2011-10-11 22:23
>>4
The
text board /sci/:
http://dis.4chan.org/sci/
moot was a bit of a dick when he named the image board. I guess /sm/ would risk too many people drawing connections with the
old /sm/...
Name:
Anonymous
2011-10-11 22:24
ok thanks guys!
Name:
Anonymous
2011-10-11 23:14
I'm not very well versed in mathematics but is this right?
(x+y)/3 = sqrt(xy)
x+y = 9xy
x/y + 1 = 9x
x/y = 9x - 1
Name:
Anonymous
2011-10-11 23:18
Have you tried wolframalpha? It's the one good thing Wolfram has done.
Name:
Anonymous
2011-10-11 23:49
>>7
No wait that's obviously wrong,
x^2 + y^2 = 7xy
Just like the OP... However, try solving it as a quadratic polynomial with respect to x.
x^2 - 7xy + y^2 = 0
x = (7y + sqrt(49y^2 - 4y^2))/2
2x = y (7 + 3sqrt(5))
x/y = (7 + 3sqrt(5))/2
I don't know if you're supposed to take the other solution into account.
Name:
Anonymous
2011-10-12 2:32
How cute. OP think that we have rules on our /prog/.
This is so aodorable, guys.
Name:
Anonymous
2011-10-12 8:38
>>10
We
do have rules. Y'know, on the rules page.
What we lack are competent moderators who enforce those rules.
>>11 nice dubz btw
lolol is ur /prob/ ded
U MENA FARTISM
Name:
Anonymous
2014-02-14 11:09
[code]tags do existfor a reason,you know.