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I hope this is allowed

Name: Anonymous 2011-10-11 22:04

I tried to find the rules for this board, but couldn't find them.

I hope I'm not breaking any. I also hope someone can help me (/sci/ doesn't allow these threads).

Can you help me with a tiny math problem?

log((x+y)/3)=(1/2)(log(x)+log(y)), determine the value of x/y

I keep ending up with (x^2)+(y^2)-(7xy)=0

any suggestions? It's driving me nuts...

Name: Anonymous 2011-10-12 8:38

>>10
We do have rules. Y'know, on the rules page.
What we lack are competent moderators who enforce those rules.

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