I MENA HASKAL

Is there any way to do something like this in Haskell?

f g = (g 1, g 'a') -- f id should return (1, 'a')

This is a simplified example, my problem is that I have a function that takes a function of type ([a] -> b) -> b and I want to use it twice, once as ([a] -> [a]) -> [a] and once as ([a] -> a) -> a.

Thanks.

lolol is ur dof ded

U MENA HASKAL

>>2
Thanks for your help.

But yeah, after thinking about the problem I realized why what I'm trying to do shouldn't be allowed. So is there a better way to do this?

I'm not too big on Haskell, but if I'm reading what you want to do right, you'd pretty much need a macro. Maybe you could do it with Template Haskell, but I've never used it.

And I'm not sure why you would use that retarded title on a presumably serious post, except to attract spam.

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y'oure welcome's

>>5 fucking shit wrong thread again. i hate posting from a cellphone