I MENA HASKAL

Is there any way to do something like this in Haskell?

f g = (g 1, g 'a') -- f id should return (1, 'a')

This is a simplified example, my problem is that I have a function that takes a function of type ([a] -> b) -> b and I want to use it twice, once as ([a] -> [a]) -> [a] and once as ([a] -> a) -> a.

Thanks.

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