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http://www.mceniry.net/papers/Fast%20Inverse%20Square%20Root.pdf

So fucking old it's not funny.
Get the fuck out

>>1
double fast_inverse_square_root(double x)
{
    return x * x;
}
How difficult was that?

how about that sicp girl

>>3
Holy shit I benchmarked this against the one in the paper and this one blows it away. Why hasn't this been publisehed?

>>5
x² ≠ x^-0.5

>>6
the inverse function of the square root function is the square function

>>7
"inverse square root" ≠ "inverse of square root"

>>8
Actually, it does. (/ (sqrt x)) is the inverse of the square root of x).

>>9
(inverse of square root) x ≠ inverse of the square root of x

>>11
(inverse of square root) is interpreted as the inverse to the square root function, which is the square function, the only difference being "the", "the" itself does not distinguish context

>>12
inverse square root of x == inverse of (square root of x)
inverse of (square root of x) /= (inverse of square root) x

>>12
Let f(x) = x², Domain: [0,inf); Range: [0,inf)
Then f^-1(x) = sqrt(x), Domain: [0,inf); Range: [0,inf)

Inverse square root = f^-1(f^-1), (Definition of a function inverse)

Therefore, inverse square root of any value of x = x²

This is the same for the "Inverse of the square root x" which is saying "take a function that is the inverse of the square root function and apply it to x. In the same sense you would say "f of x" you substitute f for your function and get "inverse of square root of x."

function inverseSQ(x){return 1/(Math.sqrt(x))}

alert(inverseSQ(0)+inverseSQ(-1));
//nice error checking faggot, gb2/kpanic/

>>15
function safeiSQ(x){
if(isNaN(x) || x==Infinity){return 'Invalid number'}else{
var r=1/(Math.sqrt(x))
if(isNaN(r) || r==Infinity){return 'Invalid number'}else{
return r
 }}}

>>16
safeiSQ(0)
safeiSQ(-1)
still broken.

>>13
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