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Name: Anonymous 2009-03-16 16:47

Name: Anonymous 2009-03-17 4:34

>>12
Let f(x) = x2, Domain: [0,inf); Range: [0,inf)
Then f-1(x) = sqrt(x), Domain: [0,inf); Range: [0,inf)

Inverse square root = f-1(f-1), (Definition of a function inverse)

Therefore, inverse square root of any value of x = x2

This is the same for the "Inverse of the square root x" which is saying "take a function that is the inverse of the square root function and apply it to x. In the same sense you would say "f of x" you substitute f for your function and get "inverse of square root of x."

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