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Number Series

Name: _ 2012-12-02 21:44

write integral (from 0 to 1) of 1/(8+x^3) dx as the summation of a number series

Name: Anonymous 2012-12-04 16:40

We are too stupid to do your homework.

Name: Anonymous 2012-12-05 2:16

Shut the fuck up Anon. I will gladly do OP's homework.

Name: Anonymous 2012-12-08 18:31

\int_{0}^{1} \frac{1}{8+x^{3}} dx as the summation of a number series.

Name: Anonymous 2012-12-10 19:08

But what does it mean?

Name: Anonymous 2012-12-16 20:32

\lim_{n\rightarrow \infty }\sum_{i=1}^{n } \frac{1}{8+(\frac{i}{n})^{3}}

Name: Anonymous 2012-12-16 20:36

>>6

then divide by n

Name: Anonymous 2012-12-16 20:39

\lim_{n\rightarrow \infty } \frac{1}{n}\sum_{i=1}^{n } \frac{1}{8+(\frac{i}{n})^{3}}

Name: Anonymous 2013-01-11 22:52

You can taylor series around x=0:
[eqn] \int_{0}^{1} \frac{8}{1+(x/2)^3} dx = 4 \int_0^2 \frac{1}{1+x^3}=4 \int_0^2 \sum_{n=0}^{\inf} (-1)^n (x^{3n})[\eqn]

That reduces to:
[eqn] \sum_{n=0}^{\inf} 2\frac{(-8)^n}{3n} [\eqn]

Name: Anonymous 2013-01-12 9:10


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