Integration

Need help with some integration

f'(x)= 3(2x-1)^2

How do I integrate using the rule;

f(x)= 1/a*(f(x)^n+1)/n+1

When there is a coefficient in front of the brackets? I'm almost certain you don't expand. Any help please.

>>1
You can re-express as (1/3)f'(x)= (2x-1)^2 and continue as normal, just with the factor (1/3) tacked on.  There's a rule about integrating a constant times a function is the same as the constant times the integral of the funtion:  http://myhandbook.info/pics/integ/integ02.gif

So to clarify, with your rule you get 3/a*(f(x)^n+1)/n+1