Interesting

[tex]x^x^3 = 3[/tex]
solve. Then solve
[tex]x^x^x^3 = 3[/tex]
thoughts?

Ok I'm gonna help you, the solution for the first one is 3^1/3. What's the roots for x^x^x^3 = 3

You fucking retards dont find this interesting at all?

Say, apparently x^x^x^3 = 3 also has solution is cube root of 3.

>>4
and in fact if f_n(x; a) = x^x^x^x ... ^x^a, then f_n(a^1/a; a) = a

(I don't know how this can be expressed using Knuth's up arrow notation http://en.wikipedia.org/wiki/Knuth%27s_up-arrow_notation but perhaps it is better expressed that way)

Knowing all this, your task now is to find the set of convergence of x^x^x^x^...

(hint: familiar constants will get in the way...)

x^y =/= y^x

parentheses are needed

You want to know something interesting:
Take a number m and separate the rightmost digit from the rest of the number.  Take that rightmost digit and multiply it by -20 and add it to the rest (for example, 134 -> 4 * -20 + 13).  If the end result is divisible by 67, so is the original number.