Name:
Anonymous
2011-03-04 11:44
What is an example of a module that is not a free module? (Assuming axiom of choice, so it can't be a vector space)
Name:
Anonymous
2011-03-05 16:38
Z/<2> is a module over Z, that is not free.
Name:
Anonymous
2011-03-06 2:58
>>2
Really? This is probably really stupid, but why not? Doesn't 2Z + 1 generate it?
Name:
Anonymous
2011-03-07 11:05
>>3
Yeah, but not freely. Technically you also need linear independence which isn't the case here (just multiply it by 2).
Name:
Anonymous
2011-03-08 10:56
>>5
No problem. Keep slaving away for those mods.