How do I differentiate x^2 + y^2 = constant^2 with respect to time in order to find the velocities?
Name:
Anonymous2011-01-17 17:42
>>1
You can't; at least, you can't and expect to get anything substantial. Unless "x" or "y" don't mean classical "x" and "y" concepts, there is no time factored into that equation.
>>3
It doesn't matter. A constant always differentiates to 0 and frequency IS a velocity in a manner of speaking (events per time interval) besides that.