okay haha

okay, since this is 4:54 am I'm not really sure about what to do
if x is moving with 3 speed units towards direction 90 (in degrees), and gains 6 speed units towards direction 180, how do I calculate x's final speed and direction?
dont just give me the answer to WHAT its final speed and direction is, tell me how you calculate it.

Lets simplify it:
X is a cool guy and he sweeps towards a blonde chick with 3 speed units, then wow, he finds out that awesome chick on the other end of the room, so now he cant make up his mind and his dick is pulling him to both of em simultaneously, coz hes a hard guy and likes as much as possible. But the 6 speed units chick is prettier, so sine function that stares on his trail toward her has a higher angle than the one that stares on the 3-speed trail, his dick however doesnt know that and pulls him with force that moves him with speed equal to the length of vector that is drawn on both his basic speed vectors, his direction being such an easy question that not being native speaker i grow bored of translating lol, anyway using trygonomethric functions to count it, tang (3/6) is your angle, then cosinus of that angle is equal to 6/speed(x), its direction is vector [6,3], angle equal to tan(3/6), taken speed 6 is the x and speed 3 lies on  y,

you are adding 2-d vectors.


you add x1 to x2 and y1 to y2 and then that is your final vector.