You should be able to solve this

(sqrt((a-b)^2+(c-d)^2+(e-f)^2))^3

does sqrt = square-root?

:/

this is worse than LISP code

Not here to help you with your math homework. Go back to reddit.

(a-b)⁶ + (c-d)⁶ + (e-f)⁶

thats as far as I can take it

whoops change 6 to 3

(sqrt( (a-b)^2 + (c-d)^2 + (e-f)^2 ))^3
( (a-b)^2 + (c-d)^2 + (e-f)^2 )^(3/2)
(a^2 - 2ab + b^2 + c^2 - 2cd + d^2 + e^2 - 2ef + f^2)^(3/2)
... I am not cubing that.  You can't make me.

( (a-b)^2 + (c-d)^2 + (e-f)^2 )^(3/2)
( ((a-b)^2 + (c-d)^2 + (e-f)^2)((a-b)^2 + (c-d)^2 + (e-f)^2)((a-b)^2 + (c-d)^2 + (e-f)^2) )^(1/2)

-(a-b)^4 + ((a-b)(c-d))^2 + ((a-b)(e-f))^2
-((a-b)(c-d))^2 + (c-d)^4 + ((c-d)(e-f))^2
-((a-b)(e-f))^2 + ((c-d)(e-f))^2 + (e-f)^4

( ((a-b)^4 + (c-d)^4 + (e-f)^4 + 2((a-b)(c-d))^2 + 2((c-d)(e-f))^2 + 2((a-b)(e-f))^2)((a-b)^2 + (c-d)^2 + (e-f)^2) )^(1/2)

-(a-b)^6 + (a-b)^2(c-d)^4 + (a-b)^2(e-f)^4 + 2(a-b)^4(c-d)^2 + 2((a-b)(c-d)(e-f))^2 + 2(a-b)^4(e-f)^2
-(a-b)^4(c-d)^2 + (c-d)^6 + (c-d)^2(e-f)^4 + 2(a-b)^2(c-d)^4 + 2(c-d)^4(e-f)^2 + 2((a-b)(c-d)(e-f))^2
-(a-b)^4(e-f)^2 + (c-d)^4(e-f)^2 + (e-f)^6 + 2((a-b)(c-d)(e-f))^2 + 2(c-d)^2(e-f)^4 + 2(a-b)^2(e-f)^4

= ( (a-b)^6 + (c-d)^6 + (e-f)^6 + 6((a-b)(c-d)(e-f))^2 + 3(a-b)^2(c-d)^4 + 3(a-b)^2(e-f)^4 + 3(a-b)^4(e-f)^2 + 3(c-d)^2(e-f)^4 + 3(c-d)^4(e-f)^2 + 3(a-b)^4(c-d)^2 )^(1/2)

... this is not worth it.

((a-b)^2+(c-d)^2+(e-f)^2)^(3/2)
= a^2*sqrt((a-b)^2+(c-d)^2+(e-f)^2)+b^2*sqrt((a-b)^2+(c-d)^2+(e-f)^2)+c^2*sqrt((a-b)^2+(c-d)^2+(e-f)^2)+d^2*sqrt((a-b)^2+(c-d)^2+(e-f)^2)+e^2*sqrt((a-b)^2+(c-d)^2+(e-f)^2)+f^2*sqrt((a-b)^2+(c-d)^2+(e-f)^2)-2*a*b*sqrt((a-b)^2+(c-d)^2+(e-f)^2)-2*e*f sqrt((a-b)^2+(c-d)^2+(e-f)^2)-2*c*d*sqrt((a-b)^2+(c-d)^2+(e-f)^2)

>>7
How comes the power of half doesn't cancel with squared at :

( (a-b)^2 + (c-d)^2 + (e-f)^2 )^(3/2)

>>10
You can't distribute an exponent over an expression that includes addition or subtraction at the same level.  To prove that, try this:

sqrt(5-2) != sqrt(5) - sqrt(2)

You could do this only in the case of multiplication or division at the same level.  This is also the reason that you have to multiply the whole expression by itself three times (power of three).

(a-b)^2 = (a-b)(a-b) = a^2 - 2ab + b^2
(a-b)^3 = (a-b)(a-b)(a-b) = (a^2 - 2ab + b^2)(a-b) = a^3 - b^3 - 3(a^2)b + 3a(b^2)

>>1
This isn't even an equation.  What is there to solve?

http://tinychat.com/8t8cw