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Polynomials

Name: Anonymous 2010-02-09 5:10

I feel like such an idiot. I cannot for the life of me remember how to solve for x in terms of y when dealing with a polynomial.

I'm given y=4+3x-x^2 and I keep getting stuck with x on both sides and I can't figure out how to get down to one side. I know there's a really easy way to do this, but it's been so long... :(

I found some equation that was like x=(y/a-e)^(1/2)-b/a, where e is (b/a)^(1/2), but that returned imaginary numbers.

Please help a desperate anon out.
Can someone help a poor, desperate anon out?

Name: Anonymous 2010-02-09 5:11

>Please help a desperate anon out.
>Can someone help a poor, desperate anon out?
And I am clearly very tired. I've been doing Calc II for the last 6 hours. Ignore anything dumb I say, like that.

Name: Anonymous 2010-02-09 7:31


\begin{align*}
y &= ax^2+bx+c \\
0 &= ax^2+bx+c-y \\
x &= \tfrac{-b\pm\sqrt{b^2-4a(c-y)}}{2a}
\end{align*}

Name: Anonymous 2010-02-11 12:48


Don't change these.
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