Name: Anonymous 2009-11-04 19:06
1.show that the points A(1,2,-3) B(0,2,4) C(-3,6,-1) are non collinear.
2.then using points ABC find the vector equation and linear equation.
for number 2, i got 2 direction vectors AB and AC and used Point A as the normal vector so I have [x,y,z]=[A]+t[AB]+s[AC] where T,S, ER.
i'm not sure if this is right, looking for help of any kind please. I'm completely stuck on question 1 and i'm not sure how to do question 2.
2.then using points ABC find the vector equation and linear equation.
for number 2, i got 2 direction vectors AB and AC and used Point A as the normal vector so I have [x,y,z]=[A]+t[AB]+s[AC] where T,S, ER.
i'm not sure if this is right, looking for help of any kind please. I'm completely stuck on question 1 and i'm not sure how to do question 2.