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Sound Wave

Name: Anonymous 2009-10-02 9:25

A sound wave produces a pressure variation given by

p(x,t)=0.5sin[(pi/4) (x-720t)

p in Pascals, x in metres and t in seconds.

From the general for of a soudn wave wave function;
p(x,t)=BkA sin (kx-wt) I've found the pressure amplitude by
p(max)=BkA=0.5P

I've been asked to find the frequency and wavelength as well,

I used f=w/2pi and lambda=2pi/k and came out with f=90Hz and lambda=8m

Do these answers sound sensible?

Name: Anonymous 2009-10-03 10:29

bump?

Name: Anonymous 2009-10-03 20:02

yeah it looks good.

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