Name:
LJ
2009-08-27 21:48
(x^2 - 5)^2 - 5
I have never squared an already squared factor like this, I have no idea how to approach it.
Name:
Anonymous
2009-08-28 4:16
(x^2 - 5)^2 - 5
=
x^2^2 - 5^2 - 5
=
4x - 5
done
Name:
Anonymous
2009-08-28 4:28
lrn2binomial
(x^2-5)^2-5
= x^2^2 - 10x^2 + 25 - 5
= x^4 - 10x^2 + 20
Name:
Anonymous
2009-08-28 4:31
also
(x^2)^2 (forgot the () above) = x^2 * x^2 = x^(2+2) = x^4
in general:
(x^y)^z = x^(y*z)
BUT
x^y^z = x^(y^z), so be careful with your parentheses
see
http://en.wikipedia.org/wiki/Exponentiation#Identities_and_properties
Name:
Anonymous
2009-08-30 18:38
I don't know how people have difficulties with elementary algebra beyond the first few days or so.