Equation

PLEASE, /sci/, I need your help!

Here's the equation:
8*3^{x+\sqrt{x}}=9^x-9^{\sqrt{x}+1}

I can't solve it. I tried many things, but I fail every single time. I know the answer (which Mathematica/Wolfram|Alpha gave me) but that's not what I want.
What I need is a step-by-step solution or some good hints.

I'll be very glad if you help me out.
Thanks in advance.

Protip: Spambomb moot until he gets his lazy ass together and puts in a Delete feature on the textboards. :/

>>6
Sure it does.

\log 3^x = \log -3^{\sqrt{x}}
x = \log {-1} + \sqrt{x}  + 2\pi i n
\sqrt{x}^2 - \sqrt{x} - (2n+1) \pi i = 0
\sqrt{x} = \frac{1 \pm \sqrt{1+4(2n+1)\pi i}}{2}
x = \left[\frac{1 \pm \sqrt{1+4(2n+1)\pi i}}{2}\right]^2