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is this true?

Name: Anonymous 2009-05-19 21:58

[0,Pi)U(Pi,4] = [0,4]

Name: Anonymous 2009-05-19 23:07

I don't think so; that looks like it would = {x|0<=x<=4, x!=pi}. I don't think that pi, being excluded in both original sets can suddenly be included in the union.

I could be wrong, but...

Name: Anonymous 2009-05-19 23:52

>>2
You're right.

Name: Anonymous 2009-05-30 22:20


aest = 13
test = 3

Don't change these.
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