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I need help with my maths.

Name: Anonymous 2009-03-27 4:14

http://mathbin.net/7351

Free blowjays for everyone who helps me!

Name: Anonymous 2009-03-27 4:22

Apply the cosine sum/difference formula under "Angle sum and difference identities" at http://en.wikipedia.org/wiki/List_of_trigonometric_identities

Name: Anonymous 2009-03-27 4:57

I've got most of it done now, but I can't figure out how to get I_0.

Name: Anonymous 2009-03-27 5:26

Never mind, I figured it out. Thanks.

Name: Anonymous 2009-03-27 16:20

>>1
>I need help with my maths.
>my maths.
>maths.
RRRRRRRRRRRAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAGGGGGGGGGGGGGGGGGGGGEEEEEEEEEEEEEEEEEEEEEEEEEEE!!!!!!!!!!!!!!!!!!!!!!!

Name: Anonymous 2009-03-31 12:11

>>5
I RAGE AT YOUR RAGE YOU AMERICAN PIG DOG

Name: Anonymous 2009-04-02 13:13

Hey /sci/. I need help because I smoked too much pot in high school.

A car traveling 15 m/s speeds up to 25 m/s in 125 m. How much time does it take the car to do this?

A certain automobile manufacturer claims that its sports car will accelerate uniformly from rest to a speed of 27 m/s in 8.0 seconds. What is the acceleration of the car? How far does the car travel during this time?

Name: Anonymous 2009-04-02 14:21

A car traveling 15 m/s speeds up to 25 m/s in 125 m. How much time does it take the car to do this?

Is unsolvable because there is no mention of jerk.

Name: Anon 2009-04-02 14:48

The latter involves less work, so dealing with that, acceleration is change in velocity divided by change in time, so 27m/8s^2 or 3.375m/s^2.  For distance traveled, you'll rely on the handy formula

Distance = Initial Velocity x Time + 1/2 x Acceleration x Time^2;

d = 0m/s x 8s + 1/2 x (27m/8s^2) x (8s)^2 =
= 0 + 1/2 x 27m x 8 = 27m x 4 = 108m.

For the first problem, assuming uniform acceleration, it requires the same distance formula, only the acceleration can't simply be plugged in.  But the distance formula can be thought of as

Distance = Initial Velocity x Time + 1/2 x (Acceleration x Time) x Time,

and finding out Acceleration x Time is easy enough with the formula

Initial Velocity + Acceleration x Time = Final Velocity,

15m/s + Acceleration x Time = 25m/s
Acceleration x Time = 10m/s

Plugging everything known into the distance formula yields

125m = 15m/s x Time + 1/2 x 10m/s x Time
125m = 15m/s x Time + 5m/s x Time
125m = 20m/s x Time
6.25 s = Time

Name: Anonymous 2009-04-08 17:38

YOur wrong mother fucker

Name: Anonymous 2009-04-10 18:09

>>10
Easy said. Explain why his position is wrong and maybe someone will believe your point.

Name: Anonymous 2009-04-11 12:05

>>11
You misunderstand, he said "YOur wrong mother fuck", not "you're wrong mother fucker"

Name: Anonymous 2009-04-11 12:08

Boy, I do wish Shiitchan had a permasage function.

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