Statistic Sample distributions help

Hey /sci/ wondering if anyone could help me with this problem.

Four friends meet for an evening of cards. Being an experienced poker player, Alex has a greater chance than his three friends of winning any given round of poker. It is known that for every round of poker,
        P("Alex wins") = 0.56     P("David wins") = 0.24
It is assumed that what happens on each round of poker is independent from the results of the previous rounds.

What is the probability that Alex would win at least 9 out of the next 10 rounds of poker?

I have the solution to this, but I cant figure out how it is calculated. It would be much appreciated if someone could help.

OK, since the question just asks about Alex, we can completely ignore the David information as extraneous.  The situation is binary:  on any trial (round), Alex wins, or Alex does not win.  P(A)=0.56, P(not A)=0.44.

To answer probability for "win at least 9 of 10", find the probability for "win exactly 9 of 10" and "win exactly 10 of 10", and add the two probabilities together.

The formula for binomial probability for k successes out of n trials is given by _nC_kp^k(1 - p)^{n - k}, where _nC_k is the number of combinations of choosing k items from a set of n items.  Your calculator may have a key with that formula built in, or you may even have a TI graphing calculator as is common in schools now that has binomial probability function built in too.

Also, don't forget that the question specifies Alex winning "at least 9" rather than "exactly 9" out of ten rounds.

=BINOMDIST(9,10,0.54,FALSE)+BINOMDIST(10,10,0.54,FALSE)

this is how i roll