Unit cells

I'm just learning unit cells, and this question came up and I don't know how to find the solution

"The density of iron is 7860 kg/m3 and the cell volume is 2.35 x 10-23 cm3. Determine the number of atoms in the unit cell. Note: the number of atoms in a unit cell is a whole number."

I got the question wrong already (answer was 4)

HOW THE FUCK IS IT 4

Step-by-step please?

4, in this case, is a constant.

(2.35*10^-23)cm^3 *  (7860 kg/m^3) / YHBT

Also Avogadro

>>3
BTW if you google "(2.35*10^-23)cm^3 *  (7860 kg/m^3)" you'll get an answer in kilos. If you can't go from kilos to atoms you deserve to have your anus haxed.

[math]\mathbb{Q}(\sqrt{2})[\math]

[math]afdsdfs[\math]