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Integrals

Name: Anonymous 2009-01-29 7:34

what is the integral of
(sin2x)^3
- working needed
also need integral of
(tan(x/2))^2 - book's hint: (sec(x/2))^2 - 1

ty in advance

Name: Anonymous 2009-01-29 7:51

If you don't do it yourself, how will you learn

Name: Anonymous 2009-01-29 7:57

You have sin(2x)^3 = sin(2x)(sin(2x)^2)=sin(2x)(1-cos(2x)^2)

Now try substitution and see if you can do it. I have to go to work so that's as far as i'm taking you.

Name: Anonymous 2009-01-30 10:51

OP here: <3 anon - figured out the second one with a hint in the book, thank's for the hint i got them both now

Name: Anonymous 2009-01-30 10:51

thanks*

Name: mo‮8pE! to‬pui‮ !1uHaijp7IU!n9e4aOufPFUPnvI 2009-01-31 5:31

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Name: Anonymous 2009-02-01 20:30

let u = sin2x
du/dx=2cos2x

The integral becomes int {u^3 * dx/du * du}
=1/4U^4*2cos2x
Put U back in terms of x

1/2*cos(2x)(sin(2x))^4

Don't change these.
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