Integrals
Name:
Anonymous
2009-01-29 7:34
what is the integral of
(sin2x)^3
- working needed
also need integral of
(tan(x/2))^2 - book's hint: (sec(x/2))^2 - 1
ty in advance
Name:
Anonymous
2009-01-29 7:51
If you don't do it yourself, how will you learn
Name:
Anonymous
2009-01-29 7:57
You have sin(2x)^3 = sin(2x)(sin(2x)^2)=sin(2x)(1-cos(2x)^2)
Now try substitution and see if you can do it. I have to go to work so that's as far as i'm taking you.
Name:
Anonymous
2009-01-30 10:51
OP here: <3 anon - figured out the second one with a hint in the book, thank's for the hint i got them both now
Name:
Anonymous
2009-01-30 10:51
thanks*
Name:
mo8pE! topui
!1uHaijp7IU!n9e4aOufPFUPnvI
2009-01-31 5:31
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Name:
Anonymous
2009-02-01 20:30
let u = sin2x
du/dx=2cos2x
The integral becomes int {u^3 * dx/du * du}
=1/4U^4*2cos2x
Put U back in terms of x
1/2*cos(2x)(sin(2x))^4