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Quick Integral Help

Name: Anonymous 2009-01-15 18:21

How would you integrate  1/(u^3+ u) ?  The background is needing to solve the integral of  tanh(x)  two ways - The Hyperbolic substitution part is easy, by we are also told to replace tanh(x) with it's e^x equivalent of  (exp(x) - exp(-x)) / (exp(x) + exp(-x))  , substitute u for e^x, and solve from there.

You end up with two integrals - u/(u^2 +1) , simple, and 1/(u^3 + u) , less simple. What route should I take from here? Am I missing some subtle clue?

Name: Anonymous 2009-01-15 19:57

Rewrite as 1/u(u^2+1)
Substitute u^2 + 1
Partial fraction decomposition and you got it

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