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studiez

Name: Anonymous 2008-12-27 23:52

No Study = Fail

Study = No Fail

(1+No)Study = (1+No)Fail

Study = Fail

wat

Name: Anonymous 2008-12-28 1:28

1+ no = yes ,  Lets intergrate this bitch.

Name: Anonymous 2008-12-28 8:24

Study = Might no fail.

Name: Anonymous 2008-12-28 9:41

It's wrong. 1+No=0

Name: Anonymous 2008-12-28 11:43

>>1
you assume the system is commutative

Name: Anonymous 2008-12-28 12:06

so  0=Yes?      horrible system

Name: Anonymous 2008-12-31 3:02

WRONG.

Study = Fail / No
Study = No Fail

No Fail = Fail / No

No^2 = 1

lulz.

Name: Anonymous 2009-01-01 22:16

1) Study = No + Fail
2) No + Study = Fail
Rearrange to solve for No
1) No = Study - Fail
2) No = Fail - Study

Sub 1) into 2)
Study - Fail = Fail - Study

2(Study) = 2(Fail)

2 Study is 2 Fail

To study is to fail.





wat?

Name: Anonymous 2009-01-03 7:51

No is a unary operator(boolean logic). It follows different rules from normal arithimethic, and you can't treat an operator as a value. If you really want something similar, you'd use multiplication with -1 in math.
So you'd write:

No = -1

No*Study = Fail

Study = No*Fail

(1+No)Study = (1+No)Fail

0*Study = Fail*0
you can't divide by zero, if you wanted to have a non -1 value for No, you'd have:

1+No != 0
,
Study != Fail
<=>
(1+No)Study != (1+No)Fail

In general, this does not make any sense without defining the operations and elements on which they work, as well as the axioms that govern your system. A boolean logic system would work for you, but your equations wouldn't work in it of course.

Name: Anonymous 2009-01-03 18:14

fail fail fail fail fail fail

Name: Anonymous 2009-01-03 19:52

No = 0
Yes = 1
Apply binary.

Yes Yes No No Yes Yes No Yes Yes No Yes No Yes No No Yes Yes No No No Yes Yes No Yes Yes Yes No No Yes No Yes Yes Yes Yes Yes No

Now shout that in bed.

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