Cengage
Name:
Anonymous
2008-12-08 16:17
does any one have the answers to cengage accounting 1 answers, specifically ch 5 and 6
Name:
Anonymous
2008-12-08 19:34
Go die.
Name:
Anonymous
2008-12-19 18:01
2/5\,x\sqrt {1+4\,{x}^{3}}-1/5\,i\sqrt {3}\sqrt [3]{2}\sqrt {i \left(x-1/4\,\sqrt [3]{2}-1/4\,i\sqrt {3}\sqrt [3]{2} \right)\sqrt {3}{2}^{2/3}}\sqrt {{\frac {x+1/2\,\sqrt [3]{2}} 3/4\,\sqrt [3]{2}+1/4\,i\sqrt {3}\sqrt [3]{2}}}}\sqrt {-i \left( -1/4\,\sqrt [3]{2}+1/4\,i\sqrt {3}\sqrt [3]{2} \right) \sqrt {3}{2}^{2/3}}{\it EllipticF} \left( 1/3\,\sqrt {3}\sqrt {i \left( x-1/4\,\sqrt [3]{2}-1/4\,i\sqrt {3}\sqrt [3]{2} \right) \sqrt {3}{2}^{2/3}},1/2\,\sqrt {2}\sqrt {{\frac {i\sqrt {3}\sqrt [3]{2}}3/4\,\sqrt [3]{2}+1/4\,i\sqrt {3}\sqrt [3]{2}}}} \right) {\frac {1}{\sqrt {1+4\,{x}^{3}}}}
Name:
Anonymous
2008-12-19 18:02
2/5\,x\sqrt {1+4\,{x}^{3}}-1/5\,i\sqrt {3}\sqrt [3]{2}\sqrt {i \left(
x-1/4\,\sqrt [3]{2}-1/4\,i\sqrt {3}\sqrt [3]{2} \right) \sqrt {3}{2}^{
2/3}}\sqrt {{\frac {x+1/2\,\sqrt [3]{2}}{3/4\,\sqrt [3]{2}+1/4\,i
\sqrt {3}\sqrt [3]{2}}}}\sqrt {-i \left( x-1/4\,\sqrt [3]{2}+1/4\,i
\sqrt {3}\sqrt [3]{2} \right) \sqrt {3}{2}^{2/3}}{\it EllipticF}
\left( 1/3\,\sqrt {3}\sqrt {i \left( x-1/4\,\sqrt [3]{2}-1/4\,i\sqrt
{3}\sqrt [3]{2} \right) \sqrt {3}{2}^{2/3}},1/2\,\sqrt {2}\sqrt {{
\frac {i\sqrt {3}\sqrt [3]{2}}{3/4\,\sqrt [3]{2}+1/4\,i\sqrt {3}\sqrt
[3]{2}}}} \right) {\frac {1}{\sqrt {1+4\,{x}^{3}}}}
Name:
Anonymous
2008-12-19 18:23
2/5\,x\sqrt {1+4\,{x}^{3}}-1/5\,i\sqrt {3}\sqrt [3]{2}\sqrt {i \left(x-1/4\,\sqrt [3]{2}-1/4\,i\sqrt {3}\sqrt [3]{2} \right) \sqrt {3}{2}^2/3}}\sqrt {{\frac {x+1/2\,\sqrt [3]{2}}{3/4\,\sqrt [3]{2}+1/4\,i\sqrt {3}\sqrt [3]{2}}}}\sqrt {-i \left( x-1/4\,\sqrt [3]{2}+1/4\,i\sqrt {3}\sqrt [3]{2} \right) \sqrt {3}{2}^{2/3}}{\it EllipticF} \left( 1/3\,\sqrt {3}\sqrt {i \left( x-1/4\,\sqrt [3]{2}-1/4\,i\sqrt{3}\sqrt [3]{2} \right) \sqrt {3}{2}^{2/3}},1/2\,\sqrt {2}\sqrt {{\frac {i\sqrt {3}\sqrt [3]{2}}{3/4\,\sqrt [3]{2}+1/4\,i\sqrt {3}\sqrt [3]{2}}}} \right) {\frac {1}{\sqrt {1+4\,{x}^{3}}}}
Name:
Anonymous
2008-12-19 18:24
2/5\,x\sqrt {1+4\,{x}^{3}}-1/5\,i\sqrt {3}\sqrt [3]{2}\sqrt {i \left(x-1/4\,\sqrt [3]{2}-1/4\,i\sqrt {3}\sqrt [3]{2} \right) \sqrt {3}{2}^2/3}}\sqrt {{\frac {x+1/2\,\sqrt [3]{2}}{3/4\,\sqrt [3]{2}+1/4\,i\sqrt {3}\sqrt [3]{2}}}}\sqrt {-i \left( x-1/4\,\sqrt [3]{2}+1/4\,i\sqrt {3}\sqrt [3]{2} \right) \sqrt {3}{2}^{2/3}}{\it EllipticF} \left( 1/3\,\sqrt {3}\sqrt {i \left( x-1/4\,\sqrt [3]{2}-1/4\,i\sqrt{3}\sqrt [3]{2} \right) \sqrt {3}{2}^{2/3}},1/2\,\sqrt {2}\sqrt {{\frac {i\sqrt {3}\sqrt [3]{2}}{3/4\,\sqrt [3]{2}+1/4\,i\sqrt {3}\sqrt [3]{2}}}} \right) {\frac {1}{\sqrt {1+4\,{x}^{3}}}}