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How to solve?

Name: Anonymous 2008-11-29 21:01

How do I find x?

where:
y'(x)-3y(x)=0
y(2)=5

Name: Anonymous 2008-11-29 21:53

Sure you're not trying to find y(x)?

Name: Anonymous 2008-11-29 22:30

Um, I dunno. Sure, why not.

Name: 4tran 2008-11-30 5:56

y' = 3y
y = Ce3x
5 = Ce6 (boundary condition)
C = 5e-6

gb2 calculus

Name: Anonymous 2008-11-30 19:00

y(x) = 5e^{3x - 6}

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