Name:
Anonymous
2008-11-24 2:38
Integral (tan^2(x))dx
Halp.
Name:
Anonymous
2008-11-24 3:30
tan^2(x) = sec^2(x) - 1
Integral(tan^2(x) dx) = Integral(sec^2(x) - 1 dx) = tan(x) - x.
Name:
Anonymous
2008-11-26 15:22
The pleasure of being cummed inside
Name:
Anonymous
2008-11-30 19:08
>>2
Let me help you out there.
tan^{2}(x) = sec^{2}(x) - 1
\int{tan^{2}(x)dx} = \int{sec^{2}(x) - 1 dx}
\int{sec^{2}(x) - 1 dx} = tan(x) - x + C