line in space
1
Name:
Anonymous
2008-11-16 15:08
How do I find the (Cartesian) equation of the line between (1,-1,1) and (2,-1,-2)?
2
Name:
Anonymous
2008-11-16 15:22
3
Name:
Anonymous
2008-11-16 15:37
Well I can get:
x = 1 + a
y = -1
z = 1 - 3a
from the vector equation, but then what? I'm thinking maybe x - 1 = (1 - z)/3, but what about y?
4
Name:
Anonymous
2008-11-16 16:15
You can't write a single equation for a line in three dimensions, you have to stick with the parametrized version
5
Name:
Anonymous
2008-11-17 1:01
x - 1 = (1 - z)/3
y = -1
boom.
6
Name:
rage
2008-11-17 1:23
If you look at ANY of the fucking results on the first page (at least) of that Google search, you'll find a decent enough answer, you fucking retards. Fucking rage sage.