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Help a fag with his homework

Name: Anonymous 2008-11-12 20:18

w is one of the complex roots of 1.
Show that w^2 + w + 1 = 0.

No fuckin' clue.

Name: Anonymous 2008-11-12 20:55

already shown.

Name: Anonymous 2008-11-12 21:35

Explain?

Name: Anonymous 2008-11-13 0:49

>>1
complex troots of 1 what?

Name: 4tran 2008-11-13 3:36

I think that equation is only true for the complex cube roots of 1 (multiply the equation by w, and you get the same equation back).

Name: Anonymous 2008-11-13 8:50

x^3 - 1 = 0.

w is only a solution if w^3=1.

Now divide through by (w-1)

x^3 - 1 / x - 1 = x^2 + x + 1

now w is only a solution if w^3 = 1 and w =! 1.

Obvious algebra is obvious

Name: Anonymous 2008-11-15 3:38

Can't be done. You're gay.

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