Calculus sux mah cawk.

A rectangular swimming pool with a horizontal bottom is being drained. If its length and width are 25 feet by 20 feet, and the water level is falling at the rate of 0.5 ft/min, how fast is the water draining?

I know i have to use liek the two variable and make sum equation or something, but other than that im clueless.

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250 cubic feet per minute?

okay, but how exactly did you get that?

Well if the area of the rectangle is 500 sq. feet, then when the water level goes down .5 ft. it's gone down 250 cubic feet. Not really calculus unless I'm missing something. Which could be possible.

yeah thats definitely not it. Because according to this, you need to combine the variables into one single formula. And you also have to remember that this is 3-dimensional...I think you're supposed to combine the two variables then find the derviative of that....or something along those lines.

What variables? Everything's constant.

liek...i think you are supposed to combine say, the volume formula for a rectangular prism...and the rate of change of the water level which is 0.5 ft/min....

http://www.analyzemath.com/calculus/Problems/rate_change.html

V = L*W*H

Length and width are constant. dH/dt = .5 ft/min

dv/dt = L*W*dH/dt
      = 25*20*.5 ft/min
      = 250 ft/min

yup...thats gotta be it.

sounds like you're the one sucking calculus's cock. calculus is pwning you.