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Fucking math 120

Name: Anonymous 2008-10-30 13:21

How would i solve this using logs with and without a calculator?

3^x=54
I have an idea, but when i put it into Log(54) (base 3)=X, but here i get stuck. Do i divide the log of 54 by the log of 3?

Name: Anonymous 2008-10-30 14:50

>>1
Can't be done. You're black.

Name: Anonymous 2008-10-30 14:52

Google log.

Name: Anonymous 2008-10-30 14:54

Log(54) (base 3) is already a number.

If you want to get that number without log, you'll have to use some Taylor series or some shit I guess.

Name: Anonymous 2008-10-30 15:02

Google change of base formula

Name: Anonymous 2008-10-30 18:46

log(3^x) = log(54)
x log(3) = log(54)
x = log(54)/log(3)

Name: Anonymous 2008-10-31 4:07

base3log(54) = base3log((27)(2))
 = base3log(27) + base3log(2)
 = 3 + base3log(2)

Name: Anonymous 2008-11-01 6:33

3^{x} = 54
\mbox{ln}(3^{x) = \mbox{ln}54
x \mbox{ln}3 = \mbox{ln}54
x = \frac{\mbox{ln}54}{\mbox{ln}3}
x = \mbox{ln}(\frac{54}{3})
or
x = \mbox{ln}54 - \mbox{ln}3

Name: 4tran 2008-11-01 14:23

>>8
x = \frac{\mbox{ln}54}{\mbox{ln}3}
=/=
x = \mbox{ln}(\frac{54}{3})

Name: Anonymous 2008-11-02 8:31

>>9
Aww shit nigga, my mistake. 86 line #4

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