Asian Girl need Homework Help

How much concentrated hydrochloric acid solution (36.0% HCl by mass; d = 1.18 g/mL) in milliliters, is required to produce 12.0 L of 0.234 M HCl?

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>>8


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>How much concentrated hydrochloric acid solution (36.0% HCl by mass; d = 1.18 g/mL) in milliliters, is required to produce 12.0 L of 0.234 M HCl?

LEGEND:
* means the end solution
@ means the initial HCl solution

First, find the amount of mol required in the end.
That is, the 12.0L of 0.234M HCl.
n(HCl*) = cv = 0.234x12.0 = 2.808 mol

Now, find the concentration of the intial solution.
[HCl@] = 1.18 grams per mL = 1.18/36.5 mol per mL = 0.0932 mols per mL = 32.32876 mols per litre = 32.32876 M

Since we have n(HCl*), [HCl@] and want to find v.
n = cv
2.808 = 32.32876 x v
v = 0.086585 L = 87.0 mL

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