Return Styles: Pseud0ch, Terminal, Valhalla, NES, Geocities, Blue Moon. Entire thread

fun ^ 10 x int ^ 40 = Ir2

Name: Anonymous 2008-10-11 22:59

How do I solve this equation?

Name: Anonymous 2008-10-12 11:00

>>1
Can't be done. Obama is black.

Name: Anonymous 2008-10-12 11:54

what am i solving for?

Name: Anonymous 2008-10-12 15:35

>>3
World peace.

Name: Anonymous 2008-10-12 16:21

Can't be done i'm not white.

Name: 将軍 2008-10-12 16:50

According to the formula, this world's possibility has been killed

Name: 4tran 2008-10-12 18:40

>>6
General!  Our base is under attack!

Name: Anonymous 2008-10-13 2:54

Go back to bed, Nishijou Takumi.

Name: anon 2008-12-01 17:12

I looked everywhere and I conclude that this equation is either complete nonsense made for the game/anime or it is obscure.

Name: Anonymous 2008-12-01 19:52

>>9

It clearly involves twice an electrical current and resistance, uh... an integer to the fortieth with the Cartesian product of fun to the tenth... uhhh....

Name: Anonymous 2008-12-01 20:13

stop bumping old threads faggot

>>9

Name: Pride 2010-03-20 11:53

I like Cookies

Name: Lânâ 2010-08-21 17:42

Well, with this kind of equation I´m gettin´some Chaos Head ?!

Name: Anonymous 2010-08-22 2:30

>>12
Way to bump a five year old thread.

Name: Anonymous 2010-09-02 0:45

whose eyes are those?

Name: 6sji7 2010-09-14 22:39

whose eyes are those eyes?

Name: Choriisu 2010-09-18 4:34

:)

Name: Anonymous 2010-09-18 16:32

you solve it like this.

first you eliminate some useles distractions, that have no relevance to solution. you get 0 ^ 10 * 0 ^ 40 = 0 and now it's easy to solve, it's 0=0 , so the solution is "whose eyes are those eyes?"

Name: Anonymous 2010-10-04 1:43

\sum_{i=0}^nx_i

Name: ronelm2000 2011-01-25 8:20

fun^10 x int^40 = Ir2

fun is...well fun
int is...intelligence
I is an integer
r is reality

Oh yeah, it means that fun and intelligence can be used to totally change the reality of something. An alternate reality.

Name: Sir Hart 2011-05-05 16:38

Whose eyes are those eyes?

Name: Anonymous 2011-05-07 0:28

その目誰の目

Name: Anonymous 2011-05-07 2:56

IRC FOR EXPERT MATHEMATICS

Server:  whatisthiscomputer.dyndns.org
Channel: #trollchat

Name: Grim 2011-06-28 14:00

Hey, Knight-hart,
What are you talking about?

Name: Sena-shan 2011-07-15 18:36

What you've produced may destroy the world.

Name: SHOGUN 2011-07-25 11:31

その目誰の目?

Name: Misumi 2011-08-29 16:48

What the fuck is this Taku? No wonder you can't get any girls. I wish I can stay and chat, but I'm too busy necroing threads and scoring cute girls~

Name: Anonymous 2011-08-30 20:08

... therefore God exists.

Name: Kurugaya 2011-10-16 17:13

-> hoping for srs answers on 4chan.
I srsly hope u dont do dizz, OP

Name: Anonymous 2011-10-19 21:46

その目だれの目?

Name: Anonymous 2011-10-20 13:24

This means you found the formula of the destroying earth.congratulations,never say this formula to anybody!

Name: 2011-11-22 1:06

Name: 2011-11-22 1:06

Name: Anonymous 2011-11-27 17:54

Not sure if this helps.

Here is me trying to solve it with a computer.
It seems complicated.

http://sagenb.org/home/pub/3700/

Name: Anonymous 2011-11-27 17:55

[fun == 2^(1/10)*Ir^(1/10)*e^(1/5*I*pi)/int^4, fun == 2^(1/10)*Ir^(1/10)*e^(2/5*I*pi)/int^4, fun == 2^(1/10)*Ir^(1/10)*e^(3/5*I*pi)/int^4, fun == 2^(1/10)*Ir^(1/10)*e^(4/5*I*pi)/int^4, fun == -2^(1/10)*Ir^(1/10)/int^4, fun == 2^(1/10)*Ir^(1/10)*e^(-4/5*I*pi)/int^4, fun == 2^(1/10)*Ir^(1/10)*e^(-3/5*I*pi)/int^4, fun == 2^(1/10)*Ir^(1/10)*e^(-2/5*I*pi)/int^4, fun == 2^(1/10)*Ir^(1/10)*e^(-1/5*I*pi)/int^4, fun == 2^(1/10)*Ir^(1/10)/int^4]

Name: Anonymous 2011-11-27 17:56

[int == 2^(1/40)*Ir^(1/40)*e^(1/20*I*pi)/fun^(1/4), int == 2^(1/40)*Ir^(1/40)*e^(1/10*I*pi)/fun^(1/4), int == 2^(1/40)*Ir^(1/40)*e^(3/20*I*pi)/fun^(1/4), int == 2^(1/40)*Ir^(1/40)*e^(1/5*I*pi)/fun^(1/4), int == (1/2*I + 1/2)*2^(21/40)*Ir^(1/40)/fun^(1/4), int == 2^(1/40)*Ir^(1/40)*e^(3/10*I*pi)/fun^(1/4), int == 2^(1/40)*Ir^(1/40)*e^(7/20*I*pi)/fun^(1/4), int == 2^(1/40)*Ir^(1/40)*e^(2/5*I*pi)/fun^(1/4), int == 2^(1/40)*Ir^(1/40)*e^(9/20*I*pi)/fun^(1/4), int == I*2^(1/40)*Ir^(1/40)/fun^(1/4), int == 2^(1/40)*Ir^(1/40)*e^(11/20*I*pi)/fun^(1/4), int == 2^(1/40)*Ir^(1/40)*e^(3/5*I*pi)/fun^(1/4), int == 2^(1/40)*Ir^(1/40)*e^(13/20*I*pi)/fun^(1/4), int == 2^(1/40)*Ir^(1/40)*e^(7/10*I*pi)/fun^(1/4), int == (1/2*I - 1/2)*2^(21/40)*Ir^(1/40)/fun^(1/4), int == 2^(1/40)*Ir^(1/40)*e^(4/5*I*pi)/fun^(1/4), int == 2^(1/40)*Ir^(1/40)*e^(17/20*I*pi)/fun^(1/4), int == 2^(1/40)*Ir^(1/40)*e^(9/10*I*pi)/fun^(1/4), int == 2^(1/40)*Ir^(1/40)*e^(19/20*I*pi)/fun^(1/4), int == -2^(1/40)*Ir^(1/40)/fun^(1/4), int == 2^(1/40)*Ir^(1/40)*e^(-19/20*I*pi)/fun^(1/4), int == 2^(1/40)*Ir^(1/40)*e^(-9/10*I*pi)/fun^(1/4), int == 2^(1/40)*Ir^(1/40)*e^(-17/20*I*pi)/fun^(1/4), int == 2^(1/40)*Ir^(1/40)*e^(-4/5*I*pi)/fun^(1/4), int == -(1/2*I + 1/2)*2^(21/40)*Ir^(1/40)/fun^(1/4), int == 2^(1/40)*Ir^(1/40)*e^(-7/10*I*pi)/fun^(1/4), int == 2^(1/40)*Ir^(1/40)*e^(-13/20*I*pi)/fun^(1/4), int == 2^(1/40)*Ir^(1/40)*e^(-3/5*I*pi)/fun^(1/4), int == 2^(1/40)*Ir^(1/40)*e^(-11/20*I*pi)/fun^(1/4), int == -I*2^(1/40)*Ir^(1/40)/fun^(1/4), int == 2^(1/40)*Ir^(1/40)*e^(-9/20*I*pi)/fun^(1/4), int == 2^(1/40)*Ir^(1/40)*e^(-2/5*I*pi)/fun^(1/4), int == 2^(1/40)*Ir^(1/40)*e^(-7/20*I*pi)/fun^(1/4), int == 2^(1/40)*Ir^(1/40)*e^(-3/10*I*pi)/fun^(1/4), int == -(1/2*I - 1/2)*2^(21/40)*Ir^(1/40)/fun^(1/4), int == 2^(1/40)*Ir^(1/40)*e^(-1/5*I*pi)/fun^(1/4), int == 2^(1/40)*Ir^(1/40)*e^(-3/20*I*pi)/fun^(1/4), int == 2^(1/40)*Ir^(1/40)*e^(-1/10*I*pi)/fun^(1/4), int == 2^(1/40)*Ir^(1/40)*e^(-1/20*I*pi)/fun^(1/4), int == 2^(1/40)*Ir^(1/40)/fun^(1/4)]

Name: Anonymous 2011-11-27 17:57

[Ir == 1/2*fun^10*int^40]

Name: Anonymous 2011-11-27 22:55

\newcommand{\Bold}[1]{\mathbf{#1}}\left[\mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{1}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{1}{10} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{3}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{1}{5} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{\left(i + 1\right) \, 2^{\left(\frac{21}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)}}{2 \, \mbox{fun}^{\left(\frac{1}{4}\right)}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{3}{10} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{7}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{2}{5} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{9}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{i \, 2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{11}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{3}{5} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{13}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{7}{10} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{\left(i - 1\right) \, 2^{\left(\frac{21}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)}}{2 \, \mbox{fun}^{\left(\frac{1}{4}\right)}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{4}{5} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{17}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{9}{10} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{19}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = -\frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{19}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{9}{10} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{17}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{4}{5} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = -\frac{\left(i + 1\right) \, 2^{\left(\frac{21}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)}}{2 \, \mbox{fun}^{\left(\frac{1}{4}\right)}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{7}{10} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{13}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{3}{5} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{11}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = -\frac{i \, 2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{9}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{2}{5} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{7}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{3}{10} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = -\frac{\left(i - 1\right) \, 2^{\left(\frac{21}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)}}{2 \, \mbox{fun}^{\left(\frac{1}{4}\right)}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{1}{5} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{3}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{1}{10} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{1}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)}}{\mbox{fun}^{\frac{1}{4}}}\right]

Name: Anonymous 2011-11-27 22:55

$$\newcommand{\Bold}[1]{\mathbf{#1}}\left[\mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{1}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{1}{10} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{3}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{1}{5} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{\left(i + 1\right) \, 2^{\left(\frac{21}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)}}{2 \, \mbox{fun}^{\left(\frac{1}{4}\right)}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{3}{10} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{7}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{2}{5} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{9}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{i \, 2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{11}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{3}{5} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{13}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{7}{10} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{\left(i - 1\right) \, 2^{\left(\frac{21}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)}}{2 \, \mbox{fun}^{\left(\frac{1}{4}\right)}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{4}{5} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{17}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{9}{10} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{19}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = -\frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{19}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{9}{10} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{17}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{4}{5} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = -\frac{\left(i + 1\right) \, 2^{\left(\frac{21}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)}}{2 \, \mbox{fun}^{\left(\frac{1}{4}\right)}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{7}{10} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{13}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{3}{5} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{11}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = -\frac{i \, 2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{9}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{2}{5} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{7}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{3}{10} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = -\frac{\left(i - 1\right) \, 2^{\left(\frac{21}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)}}{2 \, \mbox{fun}^{\left(\frac{1}{4}\right)}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{1}{5} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{3}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{1}{10} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{1}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)}}{\mbox{fun}^{\frac{1}{4}}}\right]
$$

Name: Anonymous 2011-11-27 22:56

$\newcommand{\Bold}[1]{\mathbf{#1}}\left[\mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{1}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{1}{10} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{3}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{1}{5} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{\left(i + 1\right) \, 2^{\left(\frac{21}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)}}{2 \, \mbox{fun}^{\left(\frac{1}{4}\right)}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{3}{10} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{7}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{2}{5} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{9}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{i \, 2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{11}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{3}{5} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{13}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{7}{10} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{\left(i - 1\right) \, 2^{\left(\frac{21}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)}}{2 \, \mbox{fun}^{\left(\frac{1}{4}\right)}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{4}{5} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{17}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{9}{10} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(\frac{19}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = -\frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{19}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{9}{10} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{17}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{4}{5} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = -\frac{\left(i + 1\right) \, 2^{\left(\frac{21}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)}}{2 \, \mbox{fun}^{\left(\frac{1}{4}\right)}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{7}{10} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{13}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{3}{5} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{11}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = -\frac{i \, 2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{9}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{2}{5} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{7}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{3}{10} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = -\frac{\left(i - 1\right) \, 2^{\left(\frac{21}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)}}{2 \, \mbox{fun}^{\left(\frac{1}{4}\right)}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{1}{5} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{3}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{1}{10} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)} e^{\left(-\frac{1}{20} i \, \pi\right)}}{\mbox{fun}^{\frac{1}{4}}}, \mbox{int} = \frac{2^{\left(\frac{1}{40}\right)} \mbox{Ir}^{\left(\frac{1}{40}\right)}}{\mbox{fun}^{\frac{1}{4}}}\right]$

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