Name:
Anonymous
2008-09-28 3:07
2x^4=16x : solve for x is imposable!
Name:
Anonymous
2008-09-28 3:28
hint you must factor then use the zero product principle.
I got to the point of:
(2x^4)-16=0
2x(x^3-8)=0
2x=0 (x^3-8)=0
x=0 and I have no idea what to do with (x^3-8)
there are 4 possable solutions:
{0,2,±1+i√3}