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Some tricky algebra

Name: Anonymous 2008-09-22 4:42

The gravitational potential enegry for a mass m at a distance R+h from the centre of the earth (where R is the radius of the earth) is -GMm/(R+h) where G is Newton's gravitational constant and M is the mass of the earth. If h << R, show that this is approximately equal to a constant (independent of h) plus mgh, where g=GM/R^2.

[Hint: write R+h = R(1+h/r) and expand (1+h/R)^(-1) using the binomial theorem.]

Name: Anonymous 2008-09-22 17:00

>>1
Cant' be done. You're black.

Name: 4tran 2008-09-22 19:53

The hint gave you the answer basically...

-GMm/(R+h) = -GMm/R(1+h/R) ~ (-GMm/R)(1-h/R) = GMmh/R2 - GMm/R = gmh + constant = mgh + constant

Don't change these.
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