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Sinus issues

Name: Anonymous 2008-09-08 21:14

1: sin(2a)=f(x)
2: sin^2(a)=g(x)

Any way to rewrite those two so the left hand sides becomes the same, without introducing any trigonometric term (sin, cos, tan) nor any dependence on a to the right hand sides?

(If anyone wants the physical background, I'm stuck on calculating the initial velocity for a thrown item where the height and length of the throw is known, but the angle isn't.)

Name: 4tran 2008-09-09 21:00

f(x) = sin(2a) = 2sin(a)cos(a)
= 2sin(a)sqrt[1 - sin^2(a)]
= 2sqrt[g(x)(1 - g(x))]

Name: Anonymous 2008-09-11 15:29

Thanks. Wasn't fun beating everything into shape with that, but it was doable.

Name: Anonymous 2008-09-11 23:23

Without using trig I managed to get that the initial velocity squared is equal to:
 = 2*g*H + g*D^2/(8*H)

Where g is the graviational constant, H is the max height, and D is the length of the throw.  I was surprised how nice it turned out.

Name: Anonymous 2008-09-12 8:45

>>1
Can't be done.
>>2,3,4 are black people.

Name: Anonymous 2008-09-12 15:31

When I have sinus issues, I rinse them with salt water.

Name: 4tran 2008-09-13 2:15

>>6
LOL
At least semi related to the thread, unlike >>5.

Name: Anonymous 2008-09-13 5:58

>>7
Self-hating black.

Name: Anonymous 2008-09-14 16:23

neti pot

Name: Anonymous 2008-09-14 17:53

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Don't change these.
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