Can someone please explain
1
Name:
Anonymous
2008-05-31 23:31
Why 0! = 1
also 1/0!
2
Name:
Anonymous
2008-05-31 23:58
3
Name:
Anonymous
2008-06-01 0:15
quick and easy
thank you /sci
4
Name:
Anonymous
2008-06-01 2:38
so 2 × (0 × 0) × 2 = 2 × (1) × 2 = 4
5
Name:
Anonymous
2008-06-01 2:48
0x0 is not an empty product sir.
6
Name:
Anonymous
2008-06-01 3:00
x! = (x!) * 1
3! = (3*2*1) * 1
2! = (2*1) * 1
1! = 1 * 1
0! = 1
This may not be the best explanation but it's how I've always thought of it.
7
Name:
Anonymous
2008-06-01 3:09
>>6
if it were
0
0*1
0*1*2
0*1*2*3
etc.. it would be rather silly
8
Name:
Anonymous
2008-06-01 4:04
>>5
do u mind im trying to spread disinformation here
9
Name:
Anonymous
2008-06-01 4:09
10
Name:
Anonymous
2008-06-01 5:56
among other things, it's useful to think of n! as the number of permutations of a set of size n. The empty set has exactly one permutation, namely, the empty function.
11
Name:
Anonymous
2008-06-01 11:18
>>10
I like to refer to it as "The NULL Set"
NULL is a a funny word.
12
Name:
GTFO
2008-06-01 22:48
GTFO, SAGE THIS SHIT TO THE BACK OF THE BUS