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Can someone please explain

Name: Anonymous 2008-05-31 23:31

Why 0! = 1





also 1/0!

Name: Anonymous 2008-05-31 23:58

Name: Anonymous 2008-06-01 0:15

quick and easy

thank you /sci

Name: Anonymous 2008-06-01 2:38

so 2 × (0 × 0) × 2 = 2 × (1) × 2 = 4

Name: Anonymous 2008-06-01 2:48

0x0 is not an empty product sir.

Name: Anonymous 2008-06-01 3:00

x! = (x!) * 1
3! = (3*2*1) * 1
2! = (2*1) * 1
1! = 1 * 1
0! = 1

This may not be the best explanation but it's how I've always thought of it.

Name: Anonymous 2008-06-01 3:09

>>6
if it were
0
0*1
0*1*2
0*1*2*3
etc.. it would be rather silly

Name: Anonymous 2008-06-01 4:04

>>5
do u mind im trying to spread disinformation here

Name: Anonymous 2008-06-01 4:09

Name: Anonymous 2008-06-01 5:56

among other things, it's useful to think of n! as the number of permutations of a set of size n.  The empty set has exactly one permutation, namely, the empty function.

Name: Anonymous 2008-06-01 11:18

>>10
I like to refer to it as "The NULL Set"

NULL is a a funny word.

Name: GTFO 2008-06-01 22:48

GTFO, SAGE THIS SHIT TO THE BACK OF THE BUS

Don't change these.
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